Server Room BTU (kw?) cooling calculation

BTU kW Ton = What kind of cooling system?

"BTU's per hour" = 3.415 BTU's per hour per watt of PC load. The assumption here is that every watt of power goes into generating heat.

Knowing the BTU's per hour allows them to calculate the cooling requirements using 12,000 BTU's per Ton.

Applying a conservative conversion factor of 1.2 kW / Ton, I come up with AC requirements of 34% of the computer load.

Here are the steps:

1) Determine the computer load in the server room in watts.

2) Multiple by computer load by 3.415 to convert to BTU/hr

3) Size your AC equipment with a minimum of this BTU/hr capacity.

4) 15 degrees C is pretty cold. Most are kept closer to 25 degrees C. You may want to "up-size" the AC equipment to keep the room that cold. If all the adjacent rooms are at 25 degrees C, the server room will also be gaining heat from the surrounding walls as well.

1KW = 3413BTU 1 ton = 12000 BTU per hour

Additionally: Room Area BTU = Length (m) x Width (m) x 337
Total Occupant BTU = Number of occupants x 400 (ideally = 0)
Equipment BTU = Total wattage for all equipment x 3.5

Lighting BTU = Total wattage for all lighting x 4.25 (ideally = 0)

7 * 400 = 2800 x 3.415 = 9562 BTU/hr = 2.8 kw 2m x 2m x 337 = 1348 BTU / hr 10910 = 3.2 kw (less than 1 ton AC unit)